正在看的db2教程是:用shell抽取，更新db2的數(shù)據(jù)。為工作需要而寫的shell處理db2數(shù)據(jù)庫(kù)的程序用shell抽取db2的數(shù)據(jù)，并進(jìn)行處理。
  #SQL文定義

SQL="SELECT AAA, BBB, CCC FROM MYTBL1"

#執(zhí)行SQL

SDATA=`db2 "$SQL"`

#返回值判斷

if [ $? -ne 0 ]

then

#顯示db2返回的錯(cuò)誤信息

echo "$SDATA"

exit 1

fi

#對(duì)取得的數(shù)據(jù)進(jìn)行處理。

echo "$SDATA" | sed -e "4,/^$/!d;/^$/d" |

while read AAA BBB CCC

do

echo "AAA IS $AAA, BBB IS $BBB, CCC IS $CCC"

done

#取得數(shù)據(jù)件數(shù)

echo "$SDATA" | sed -n -e "/^$/{1,3d;n;s/[^0-9]*\([0-9]*\)[^0-9]*/\1/;p;}" | read CNT

echo "The count of selected data is $CNT."

exit 0★更新db2的數(shù)據(jù)，并取得更新結(jié)果

  SQL="UPDATE MYTBL1 SET AAA="2005",BBB="05",CCC="12""

#執(zhí)行SQL

SDATA=`db2 -a "$SQL"`

#取得SQLCODE

echo "$SDATA" | sed -n -e "s/^.*sqlcode: \([-,0-9][0-9]*\).*/\1/p" | read SQLCODE

echo "Sqlcode is $SQLCODE."

#取得SQLSTATE

echo "$SDATA" | sed -n -e "s/^.*sqlstate: \([-,0-9][0-9]*\).*/\1/p" | read SQLSTATE

echo "Sqlstate is $SQLSTATE."

#取得更新件數(shù)(即sqlerrd的第三個(gè)值)

echo "$SDATA" | sed -n -e "/sqlerrd/s/^.*(3) \([-,0-9][0-9]*\).*/\1/p" | read UPDCNT

echo "Updated data"s count is $UPDCNT."

#取得sqlerrd的第五個(gè)值

echo "$SDATA" | sed -n -e "/sqlerrd/{n;s/^.*(5) \([-,0-9][0-9]*\).*/\1/;p;}" | read SQLERRD5

echo "Sqlerrd(5) is $SQLERRD5."